\begin{picture}(0,0)%
\includegraphics{gleichwinkliges-dreieck-h.eps}%
\end{picture}%
%
%  Created by WinFIG version 5.04 
%  METADATA <version>1.0</version> 
%
\setlength{\unitlength}{1184sp}%
%
\begingroup\makeatletter\ifx\SetFigFont\undefined%
\gdef\SetFigFont#1#2#3#4#5{%
  \reset@font\fontsize{#1}{#2pt}%
  \fontfamily{#3}\fontseries{#4}\fontshape{#5}%
  \selectfont}%
\fi\endgroup%
\begin{picture}(18835,4690)(6520,-6728)
%  METADATA <id>13</id> 
\put(14416,-4351){\makebox(0,0)[lb]{\smash{{\SetFigFont{12}{14.4}{\rmdefault}{\mddefault}{\updefault}{\color[rgb]{0,.69,.69}\begin{tabular}{c}Mittelpunkt $M$ des euklidischen Kreises,\\ welcher die hyperbolische Gerade\\durch $A$ und $B$ beschreibt\end{tabular}}%
}}}}
%  METADATA <id>9</id> 
\put(8110,-4620){\makebox(0,0)[lb]{\smash{{\SetFigFont{12}{14.4}{\rmdefault}{\mddefault}{\updefault}{\color[rgb]{1,0,0}$C$}%
}}}}
%  METADATA <id>8</id> 
\put(9509,-5939){\makebox(0,0)[lb]{\smash{{\SetFigFont{12}{14.4}{\rmdefault}{\mddefault}{\updefault}{\color[rgb]{1,0,0}$B$}%
}}}}
%  METADATA <id>17</id> 
\put(8101,-3391){\makebox(0,0)[lb]{\smash{{\SetFigFont{12}{14.4}{\rmdefault}{\mddefault}{\updefault}{\color[rgb]{.82,0,.82}$\alpha$}%
}}}}
%  METADATA <id>7</id> 
\put(9475,-3075){\makebox(0,0)[lb]{\smash{{\SetFigFont{12}{14.4}{\rmdefault}{\mddefault}{\updefault}{\color[rgb]{1,0,0}$A$}%
}}}}
%  METADATA <id>18</id> 
\put(7996,-5686){\makebox(0,0)[lb]{\smash{{\SetFigFont{12}{14.4}{\rmdefault}{\mddefault}{\updefault}{\color[rgb]{.82,0,.82}$\beta$}%
}}}}
\end{picture}%
